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JEE Main 2019Medium

Q.The pair of lines x2+xy−12y2+5x+11y−8=0x^2 + xy - 12y^2 + 5x + 11y - 8 = 0 can be written as

a
(x+4y−1)(x−3y+8)=0(x + 4y - 1)(x - 3y + 8) = 0
b
(x+4y+1)(x−3y−8)=0(x + 4y + 1)(x - 3y - 8) = 0
c
(x−4y−1)(x+3y+8)=0(x - 4y - 1)(x + 3y + 8) = 0
d
(x−4y+1)(x+3y−8)=0(x - 4y + 1)(x + 3y - 8) = 0

Correct Answer: Option A

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The pair of lines x^2 + xy - 12y^2 + 5x + 11y - 8 = 0 can ... | ParikshaNiti