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JEE Main 2024Medium

Q.The equation representing the pair of lines joining the origin to the points of intersection of the curve x2+y2−4x−2y−4=0x^2 + y^2 - 4x - 2y - 4 = 0 with the line x + y = 2 is

a
x2+2xy+y2−4x−4y=0x^2 + 2xy + y^2 - 4x - 4y = 0
b
x2−2xy+y2−4x+4y=0x^2 - 2xy + y^2 - 4x + 4y = 0
c
x2+2xy+y2=0x^2 + 2xy + y^2 = 0
d
x2−2xy+y2=0x^2 - 2xy + y^2 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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