Home/Question #3707
JEE Main 2022Medium

Q.The length of the tangent from the point (7,3) to the circle x2+y24x6y12=0x^2 + y^2 - 4x - 6y - 12 = 0 is

a
50\sqrt{50}
b
60\sqrt{60}
c
70\sqrt{70}
d
80\sqrt{80}

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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