Home/Question #3711
JEE Main 2018Medium

Q.The equation of the tangent to the circle x2+y2=5x^2 + y^2 = 5 at the point (1,-2) is

a
x2y=5x - 2y = 5
b
x+2y=5x + 2y = 5
c
x2y=5x - 2y = -5
d
x+2y=5x + 2y = -5

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here