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JEE Main 2014Medium

Q.The equation of the circle passing through (0,0) and making intercepts 3 and 4 on the axes is

a
x2+y2−3x−4y=0x^2 + y^2 - 3x - 4y = 0
b
x2+y2+3x+4y=0x^2 + y^2 + 3x + 4y = 0
c
x2+y2−3x+4y=0x^2 + y^2 - 3x + 4y = 0
d
x2+y2+3x−4y=0x^2 + y^2 + 3x - 4y = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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