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JEE Main 2009Medium

Q.The equation of the circle with centre (2,3) and radius 5 is

a
(x−2)2+(y−3)2=25(x-2)^2 + (y-3)^2 = 25
b
x2+y2−4x−6y−12=0x^2 + y^2 - 4x - 6y - 12 = 0
c
x2+y2−4x−6y+12=0x^2 + y^2 - 4x - 6y + 12 = 0
d
x2+y2−4x−6y+4=0x^2 + y^2 - 4x - 6y + 4 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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