Home/Question #3725
JEE Main 2004Medium

Q.The equation of the circle touching y-axis at (0,3) and making intercept 4 on x-axis is

a
x2+y24x6y+9=0x^2 + y^2 - 4x - 6y + 9 = 0
b
x2+y2+4x+6y+9=0x^2 + y^2 + 4x + 6y + 9 = 0
c
x2+y24x+6y+9=0x^2 + y^2 - 4x + 6y + 9 = 0
d
x2+y2+4x6y+9=0x^2 + y^2 + 4x - 6y + 9 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here