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JEE Main 2002Medium

Q.The equation of the circle passing through (1,2) and (3,4) and touching x-axis is

a
x2+y2−4x−4y+4=0x^2 + y^2 - 4x - 4y + 4 = 0
b
x2+y2−4x−4y−4=0x^2 + y^2 - 4x - 4y - 4 = 0
c
x2+y2+4x+4y+4=0x^2 + y^2 + 4x + 4y + 4 = 0
d
x2+y2+4x+4y−4=0x^2 + y^2 + 4x + 4y - 4 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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