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JEE Main 2000Medium

Q.The equation of the circle with radius √18 and touching the coordinate axes in the first quadrant is

a
(x−18)2+(y−18)2=18(x - \sqrt{18})^2 + (y - \sqrt{18})^2 = 18
b
(x+18)2+(y+18)2=18(x + \sqrt{18})^2 + (y + \sqrt{18})^2 = 18
c
(x−18)2+(y+18)2=18(x - \sqrt{18})^2 + (y + \sqrt{18})^2 = 18
d
(x+18)2+(y−18)2=18(x + \sqrt{18})^2 + (y - \sqrt{18})^2 = 18

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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