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JEE Main 2024Medium

Q.The equation of the circle whose diameter is the common chord of the circles x2+y2+2x+3y+4=0x^2 + y^2 + 2x + 3y + 4 = 0 and x2+y2+4x+5y+6=0x^2 + y^2 + 4x + 5y + 6 = 0 is

a
x2+y2+3x+4y+5=0x^2 + y^2 + 3x + 4y + 5 = 0
b
x2+y23x4y5=0x^2 + y^2 - 3x - 4y - 5 = 0
c
x2+y2+x+y+1=0x^2 + y^2 + x + y + 1 = 0
d
x2+y2xy1=0x^2 + y^2 - x - y - 1 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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