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JEE Main 2020Medium

Q.The equation of the tangent to the circle x2+y2+4x+6y+5=0x^2 + y^2 + 4x + 6y + 5 = 0 at (-4,-5) is

a
4x+5y+45=04x + 5y + 45 = 0
b
4x+5y45=04x + 5y - 45 = 0
c
4x5y+45=0 -4x - 5y + 45 = 0
d
4x5y45=0 -4x - 5y - 45 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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