Home/Question #3737
JEE Main 2018Medium

Q.The equation of the circle concentric with the circle x2+y26x+8y+16=0x^2 + y^2 - 6x + 8y + 16 = 0 and having radius twice is

a
x2+y26x+8y+25=0x^2 + y^2 - 6x + 8y + 25 = 0
b
x2+y26x+8y25=0x^2 + y^2 - 6x + 8y - 25 = 0
c
x2+y26x+8y=0x^2 + y^2 - 6x + 8y = 0
d
x2+y26x+8y+9=0x^2 + y^2 - 6x + 8y + 9 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here