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Q.The equation of the circle passing through the point (2,3) and having centre on the line x - 2y + 3 = 0 and radius √5 is

a
x2+y2+2x−4y−8=0x^2 + y^2 + 2x - 4y - 8 = 0
b
x2+y2−2x+4y−8=0x^2 + y^2 - 2x + 4y - 8 = 0
c
x2+y2−2x−4y+8=0x^2 + y^2 - 2x - 4y + 8 = 0
d
x2+y2+2x+4y+8=0x^2 + y^2 + 2x + 4y + 8 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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