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JEE Main 2016Medium

Q.The equation of the circle touching the line x = 0 at (0,3) and having radius 4 is

a
x2+(y−3)2=16x^2 + (y-3)^2 = 16
b
x2+y2−6y−7=0x^2 + y^2 - 6y - 7 = 0
c
x2+y2−6y+7=0x^2 + y^2 - 6y + 7 = 0
d
x2+(y+3)2=16x^2 + (y+3)^2 = 16

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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