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JEE Main 2013Medium

Q.The equation of the circle touching the line y = x at (1,1) and having radius √2 is

a
(x−3)2+(y−3)2=2(x-3)^2 + (y-3)^2 = 2
b
(x+1)2+(y+1)2=2(x+1)^2 + (y+1)^2 = 2
c
(x−1)2+(y−1)2=2(x-1)^2 + (y-1)^2 = 2
d
(x+3)2+(y+3)2=2(x+3)^2 + (y+3)^2 = 2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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