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JEE Main 2012Medium

Q.The equation of the circle passing through (1,1) and having common tangent x + y = 2 with the circle x^2 + y^2 = 2 is

a
x2+y2−2x−2y=0x^2 + y^2 - 2x - 2y = 0
b
x2+y2+2x+2y=0x^2 + y^2 + 2x + 2y = 0
c
x2+y2−2x+2y=0x^2 + y^2 - 2x + 2y = 0
d
x2+y2+2x−2y=0x^2 + y^2 + 2x - 2y = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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