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JEE Main 2011Medium

Q.The equation of the circle touching the line 3x + 4y = 5 at (1,1) and passing through (3,3) is

a
x2+y2−2x−2y−10=0x^2 + y^2 - 2x - 2y - 10 = 0
b
x2+y2+2x+2y+10=0x^2 + y^2 + 2x + 2y + 10 = 0
c
x2+y2−2x−2y+10=0x^2 + y^2 - 2x - 2y + 10 = 0
d
x2+y2+2x+2y−10=0x^2 + y^2 + 2x + 2y - 10 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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