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JEE Main 2009Medium

Q.The equation of the circle having normal at (3,4) as the tangent at (3,0) to the circle x2+y2=9x^2 + y^2 = 9 is

a
x2+y26x8y=0x^2 + y^2 - 6x - 8y = 0
b
x2+y2+6x+8y=0x^2 + y^2 + 6x + 8y = 0
c
x2+y26x+8y=0x^2 + y^2 - 6x + 8y = 0
d
x2+y2+6x8y=0x^2 + y^2 + 6x - 8y = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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