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JEE Main 2008Medium

Q.The length of the common chord of the circles x2+y2−2x−3=0x^2 + y^2 - 2x - 3 = 0 and x2+y2−6x−4y−3=0x^2 + y^2 - 6x - 4y - 3 = 0 is

a
10\sqrt{10}
b
2102\sqrt{10}
c
5\sqrt{5}
d
252\sqrt{5}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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