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JEE Main 2007Medium

Q.The equation of the circle touching the circle x2+y2=1x^2 + y^2 = 1 internally and passing through (0,2) is

a
x2+y2−2y−3=0x^2 + y^2 - 2y - 3 = 0
b
x2+y2+2y+3=0x^2 + y^2 + 2y + 3 = 0
c
x2+y2−2y+3=0x^2 + y^2 - 2y + 3 = 0
d
x2+y2+2y−3=0x^2 + y^2 + 2y - 3 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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