Home/Question #3753
JEE Main 2002Medium

Q.The centre of the circle 4x2+4y28x12y25=04x^2 + 4y^2 - 8x - 12y - 25 = 0 is

a
(1, 3/2)
b
(1, 1.5)
c
(2,3)
d
(1,3)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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