Home/Question #3757
JEE Main 2024Medium

Q.The number of common tangents to the circles x2+y24x6y12=0x^2 + y^2 - 4x - 6y - 12 = 0 and x2+y2+6x+18y+26=0x^2 + y^2 + 6x + 18y + 26 = 0 is

a
1
b
2
c
3
d
4

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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