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JEE Main 2023Medium

Q.The equation of the circle orthogonal to the circle x2+y2+2x+4y+1=0x^2 + y^2 + 2x + 4y + 1 = 0 and passing through (1,0) and (0,1) is

a
x2+y2−2x−2y−2=0x^2 + y^2 - 2x - 2y - 2 = 0
b
x2+y2+2x+2y+2=0x^2 + y^2 + 2x + 2y + 2 = 0
c
x2+y2−2x−2y+2=0x^2 + y^2 - 2x - 2y + 2 = 0
d
x2+y2+2x+2y−2=0x^2 + y^2 + 2x + 2y - 2 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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