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JEE Main 2020Medium

Q.The equation of the chord of the circle x2+y2=16x^2 + y^2 = 16 whose midpoint is (1,1) is

a
x+y=2x + y = 2
b
xy=0x - y = 0
c
x+y=0x + y = 0
d
xy=2x - y = 2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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