Q.The equation of the circle having the line x + y = 1 as diameter and passing through (3,5) is

x^2 + y^2 - 4x - 6y + 4 = 0

x^2 + y^2 + 4x + 6y - 4 = 0

x^2 + y^2 - 4x - 6y - 4 = 0

x^2 + y^2 + 4x + 6y + 4 = 0

The correct solution involves applying the fundamental concept to derive the final value step by step...

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