Q.The radical centre of the circles $x^2 + y^2 = 1$ , $x^2 + y^2 - 2x = 0$ and $x^2 + y^2 - 4y = 0$ is

(1,2)

(0,0)

(1,1)

(2,1)

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The radical centre of the circles x2+y2=1x^2 + y^2 = 1x2+y2=1, x2+y2−2x=0x^2 + y^2 - 2x = 0x2+y2−2x=0 and x2+y2−4y=0x^2 + y^2 - 4y = 0x2+y2−4y=0 is