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Q.The equation of the circle passing through (1,1), (2,2) and (3,3) is

a
x2+y2=0x^2 + y^2 = 0
b
x2+y24x4y=0x^2 + y^2 - 4x - 4y = 0
c
x+y=0x + y = 0
d
no such circle

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

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