Q.The equation of the circle passing through (1,0) and (0,1) and having smallest possible radius is

x^2 + y^2 - x - y = 0

x^2 + y^2 + x + y = 0

x^2 + y^2 - 2x - 2y + 1 = 0

x^2 + y^2 + 2x + 2y - 1 = 0

The correct solution involves applying the fundamental concept to derive the final value step by step...

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