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JEE Main 2010Medium

Q.The equation of the circle passing through (0,0) and having minimum radius is

a
x2+y2=0x^2 + y^2 = 0
b
x2+y2=1x^2 + y^2 = 1
c
x2+y2=4x^2 + y^2 = 4
d
none

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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