Home/Question #3773
JEE Main 2008Medium

Q.The equation of the circle passing through the origin and having the line x + y = 1 as diameter is

a
x2+y2−x−y=0x^2 + y^2 - x - y = 0
b
x2+y2+x+y=0x^2 + y^2 + x + y = 0
c
x2+y2−2x−2y=0x^2 + y^2 - 2x - 2y = 0
d
x2+y2+2x+2y=0x^2 + y^2 + 2x + 2y = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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