Home/Question #3774
JEE Main 2007Medium

Q.The equation of the circle touching the line 3x + 4y = 5 at (1,1) and passing through (5,3) is

a
x2+y26x8y+15=0x^2 + y^2 - 6x - 8y + 15 = 0
b
x2+y2+6x+8y15=0x^2 + y^2 + 6x + 8y - 15 = 0
c
x2+y26x+8y15=0x^2 + y^2 - 6x + 8y - 15 = 0
d
x2+y2+6x8y+15=0x^2 + y^2 + 6x - 8y + 15 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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