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JEE Main 2003Medium

Q.The equation of the circle with centre (1,2) and tangent to x-axis is

a
(x−1)2+(y−2)2=4(x-1)^2 + (y-2)^2 = 4
b
(x−1)2+(y−2)2=2(x-1)^2 + (y-2)^2 = 2
c
(x−1)2+(y+2)2=4(x-1)^2 + (y+2)^2 = 4
d
(x+1)2+(y−2)2=4(x+1)^2 + (y-2)^2 = 4

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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