Home/Question #3780
JEE Main 2001Medium

Q.The equation of the circle passing through (0,0), (1,0) and (0,1) is

a
x2+y2−x−y=0x^2 + y^2 - x - y = 0
b
x2+y2+x+y=0x^2 + y^2 + x + y = 0
c
x2+y2−2x−2y=0x^2 + y^2 - 2x - 2y = 0
d
x2+y2+2x+2y=0x^2 + y^2 + 2x + 2y = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here