Home/Question #3781
JEE Main 2000Medium

Q.The radical axis of the circles x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0 and x2+y2+2g′x+2f′y+c′=0x^2 + y^2 + 2g'x + 2f'y + c' = 0 is

a
2(g−g′)x+2(f−f′)y+(c−c′)=02(g - g')x + 2(f - f')y + (c - c') = 0
b
2(g+g′)x+2(f+f′)y+(c+c′)=02(g + g')x + 2(f + f')y + (c + c') = 0
c
(g−g′)x+(f−f′)y+(c−c′)=0(g - g')x + (f - f')y + (c - c') = 0
d
(g+g′)x+(f+f′)y+(c+c′)=0(g + g')x + (f + f')y + (c + c') = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here