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JEE Main 2025Medium

Q.The equation of the tangent to the parabola y2=4axy^2 = 4ax at the point (at2,2at)(at^2, 2at) is

a
ty=x+at2ty = x + at^2
b
ty=xat2ty = x - at^2
c
tx=y+at2tx = y + at^2
d
tx=yat2tx = y - at^2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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