Home/Question #3802
JEE Main 2005Medium

Q.The equation of the common tangent to the parabolas y² = 4ax and x² = 4by is

a
xb+ya=abx b + y a = a b
b
xa+yb=abx a + y b = a b
c
xbya=abx b - y a = a b
d
xayb=abx a - y b = a b

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here