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JEE Main 2021Medium

Q.The equation of the normal to the parabola y2=8xy^2 = 8x at the point (2,4) is

a
x+y6=0x + y - 6 = 0
b
xy+6=0x - y + 6 = 0
c
x+y+6=0x + y + 6 = 0
d
xy6=0x - y - 6 = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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