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JEE Main 2007Medium

Q.The equation of the chord of the parabola y² = 4ax joining points with parameters t1 and t2 is

a
y(t1+t2)=2x+4at1t2y(t1 + t2) = 2x + 4a t1 t2
b
y(t1+t2)=2x+2at1t2y(t1 + t2) = 2x + 2a t1 t2
c
y(t1+t2)=2x−2at1t2y(t1 + t2) = 2x - 2a t1 t2
d
y(t1+t2)=2x−4at1t2y(t1 + t2) = 2x - 4a t1 t2

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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