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JEE Main 2025Medium

Q.The equation of the tangent to the parabola x2=4ayx^2 = 4ay at the point (2at,at2)(2at, at^2) is

a
tx=y+at2tx = y + at^2
b
ty=x+at2ty = x + at^2
c
tx+y=at2tx + y = at^2
d
ty+x=at2ty + x = at^2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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