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Q.The length of the chord of the parabola y2=4axy^2 = 4ax whose middle point is (x1,y1) is

a
2a2+(y12a)22 \sqrt{a^2 + (y1 - 2a)^2}
b
4a(x1+a)4 \sqrt{a(x1 + a)}
c
22ax1+y122 \sqrt{2a x1 + y1^2}
d
4ax1+y12/44 \sqrt{a x1 + y1^2 / 4}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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