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JEE Main 2012Medium

Q.The equation of the chord of the parabola y2=4axy^2 = 4ax whose middle point is (x1,y1) is

a
yy1=2a(x+x1)y y1 = 2a(x + x1)
b
yy12a(x+x1)=y124ax1y y1 - 2a(x + x1) = y1^2 - 4a x1
c
yy1+2a(x+x1)=y12+4ax1y y1 + 2a(x + x1) = y1^2 + 4a x1
d
yy1=2a(x+x1)+y124ax1y y1 = 2a(x + x1) + y1^2 - 4a x1

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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