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JEE Main 2025Medium

Q.The equation of the ellipse whose foci are $(\pm 2, 0)$ and eccentricity $1/2$ is

a

\dfrac{x^2}{16} + \dfrac{y^2}{12} = 1

b

\dfrac{x^2}{16} + \dfrac{y^2}{8} = 1

c

\dfrac{x^2}{12} + \dfrac{y^2}{16} = 1

d

\dfrac{x^2}{8} + \dfrac{y^2}{16} = 1

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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