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JEE Main 2022Medium

Q.The equation of the tangent to the ellipse x2/16+y2/9=1x^2/16 + y^2/9 = 1 at the point (4,3) is

a
4x+3y=254x + 3y = 25
b
3x+4y=253x + 4y = 25
c
4x3y=254x - 3y = 25
d
3x4y=253x - 4y = 25

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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