Home/Question #3876
JEE Main 2019Medium

Q.The eccentricity of the hyperbola 9x216y218x+32y151=09x^2 - 16y^2 - 18x + 32y - 151 = 0 is

a
5/45/4
b
5/4\sqrt{5}/4
c
4/34/3
d
5/35/3

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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