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JEE Main 2009Medium

Q.The equation of the ellipse with centre at (1,2) and passing through (1,0) and (3,2) is

a
(x−1)24+(y−2)24=1\dfrac{(x-1)^2}{4} + \dfrac{(y-2)^2}{4} = 1
b
(x−1)24+(y−2)2=1\dfrac{(x-1)^2}{4} + (y-2)^2 = 1
c
(x−1)2+(y−2)24=1(x-1)^2 + \dfrac{(y-2)^2}{4} = 1
d
(x−1)29+(y−2)21=1\dfrac{(x-1)^2}{9} + \dfrac{(y-2)^2}{1} = 1

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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