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JEE Main 2005Medium

Q.The equation of the hyperbola with vertices (\pm 5,0) and foci (\pm 13,0) is

a
x225−y2144=1\dfrac{x^2}{25} - \dfrac{y^2}{144} = 1
b
x2144−y225=1\dfrac{x^2}{144} - \dfrac{y^2}{25} = 1
c
x225−y2119=1\dfrac{x^2}{25} - \dfrac{y^2}{119} = 1
d
x2119−y225=1\dfrac{x^2}{119} - \dfrac{y^2}{25} = 1

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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