Q.The equation of the hyperbola referred to its axes as axes of coordinates and passing through (3,4) with transverse axis 6 is

\dfrac{x^2}{9} - \dfrac{y^2}{16} = 1

\dfrac{y^2}{9} - \dfrac{x^2}{16} = 1

\dfrac{x^2}{16} - \dfrac{y^2}{9} = 1

\dfrac{y^2}{16} - \dfrac{x^2}{9} = 1

The correct solution involves applying the fundamental concept to derive the final value step by step...

Already a member? Login here