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JEE Main 2025Medium

Q.The equation of the common tangent to the ellipse x216+y29=1\dfrac{x^2}{16} + \dfrac{y^2}{9} = 1 and the hyperbola x2−y2=4x^2 - y^2 = 4 is

a
y=±(x+7)y = \pm (x + \sqrt{7})
b
y=±(x−7)y = \pm (x - \sqrt{7})
c
y=±7xy = \pm \sqrt{7} x
d
y=±xy = \pm x

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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