Q.The electric field at a point associated with a light wave is $E = 200 \sin^2 (3 \times 10^{15}t - 9 \times 10^6 x)$ V/m. The average energy density of the electric field is

\epsilon_0 E_0^2 / 2

\epsilon_0 E_0^2 / 4

\epsilon_0 E_0^2

2\epsilon_0 E_0^2

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The electric field at a point associated with a light wave is E=200sin⁡2(3×1015t−9×106x)E = 200 \sin^2 (3 \times 10^{15}t - 9 \times 10^6 x)E=200sin2(3×1015t−9×106x) V/m. The average energy density of the electric field is