Q.The equation of the ellipse with eccentricity 3/5 and foci on x-axis with centre at origin is

\dfrac{x^2}{25} + \dfrac{y^2}{16} = 1

\dfrac{x^2}{16} + \dfrac{y^2}{25} = 1

\dfrac{x^2}{25} + \dfrac{y^2}{9} = 1

\dfrac{x^2}{9} + \dfrac{y^2}{25} = 1

The correct solution involves applying the fundamental concept to derive the final value step by step...

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